This report was to to study Neutralization Reactions Sample Calculations 1. q = ms∆t – 1M HCl q = (acid mass(g))(base mass(g))(tf-ti)(s) q = -(50.2+26.1)(8.6)(4.184) q = -2.746 kJ 2. x mol of acid & base – 1M HCl mol HCl = (1M HCl x (50mL))/(1000mL) = 0.05 mol HCl mol NaOH = (2M NaOH x (25mL)/(1000mL) = 0.05 mol NaOH 3. mol H20 – 1M HCl mol H2O – .05mol NaOH + .05mol HCl à .05mol NaCl + […]
